to solve this question, we need to difine our variables
we have values for end points as
x1 = -8
y1 = 4
x2 = -4
y2 = -8
next we can find the slope of the equation
[tex]\begin{gathered} \text{slope}=\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{-8-4}{-4-(-8)} \\ \text{slope}=\frac{-12}{4} \\ \text{slope}=-3 \end{gathered}[/tex]step 2
let's find the mid-point using mid-point formula
[tex]\begin{gathered} md=\frac{x_1+x_2}{2},\frac{y_2+y_1}{2} \\ md=\frac{-8+(-4)}{2},\frac{-8+4}{2} \\ md=-6,-2 \end{gathered}[/tex]mid-point = (-6, -2)
now we know the perpendicular line travels (-6 , -2) and has a slope of -3
equation of a straight line => y = mx + c
we can solve for c to find the equation.
[tex]\begin{gathered} y=mx+c \\ -2=(-3)(-6)+c \\ -2=18+c \\ c=-2-18 \\ c=-20 \end{gathered}[/tex]note: m = slope
c = intercept
the equation of the perpendicular bisector can be written as
y = -3x - 20
[tex]y=-3x-20[/tex]