Given the line which passes through the points (2, 3) and (5,8) and the line that passes through the points (-7, 5) and (-12, 8).
To determine the relationship which best describes the line, the first thing we do is find the gradients of the lines.
For point A and B with coordinates:
[tex]A(x_1,y_1),B(x_2,y_2)[/tex][tex]\text{Gradient, m= }\frac{y_2-y_1}{x_2-x_1}[/tex]For points (2, 3) and (5,8)
[tex]\text{Gradient, m= }\frac{8-3}{5-2}=\frac{5}{3}[/tex]For the points (-7, 5) and (-12, 8)
[tex]\text{Gradient, m= }\frac{8-5}{-12-(-7)}=\frac{3}{-5}=-\frac{3}{5}[/tex]• Two lines are said to be ,parallel, ,if their gradients are the same.
,• Two lines are said to be ,perpendicular ,if the ,product of the gradients is -1.
Product of the two gradients
[tex]\begin{gathered} =\frac{5}{3}\times-\frac{3}{5} \\ =-1 \end{gathered}[/tex]Since the product of the gradients is -1, the two lines are said to be perpendicular.
The correct option is D