Answer:
2 x 10^(-5)
Explanation:
The linear expansivity α can be calculated using the following equation:
[tex]\Delta L=\alpha\cdot\Delta T\cdot L[/tex]Where ΔL is the change in length, ΔT is the change in temperature and L is the original length of the metal. So, replacing the values, we get:
[tex]\begin{gathered} 1.36=\alpha(95-10)(800) \\ 1.36=\alpha(85)(800) \end{gathered}[/tex]Then, solving for α, we get:
[tex]\begin{gathered} 1.36=\alpha(68000) \\ \frac{1.36}{68000}=\frac{\alpha(68000)}{68000} \\ 2\times10^{-5}=\alpha \end{gathered}[/tex]Therefore, the linear expansivity of the metal is 2 x 10^(-5)
