This specimen steel alloy experience a strain fracture toughness when exposed to the stress of 927MPa
The stress intensity represents the degree of "stress" at the crack's tip. The highest stress intensity that a material can withstand without breaking under very specific (plane-strain) conditions is known as fracture toughness.
We are to determine whether or not the 4340 steel alloy specimen will fracture when exposed to a stress of 1000 MPa, given the values of KIc, Y, and the largest value of an in the material.
we solve for σc
σc=Kk/Y√πa
=45 mpa√ m/(1.0) √(π) 0.75 ×10^-3 m
=927MPa
Therefore, it is likely that this specimen will fracture because it can withstand a stress of 927 MPa, which is less than the applied stress of 1000 MPa, before breaking.
Learn more about plane fracture toughness here:https://brainly.com/question/15320813
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