S={-1}
1) Let's solve this equation.
8x² +16x +8
2) Notice that the discriminant yields 0
[tex]\begin{gathered} \Delta=b^2-4ac \\ \Delta=16^2-4(8)(8)=-240 \\ x=\frac{-b\pm\sqrt[]{\Delta}}{2a}=\frac{-16\pm\sqrt[]{0}}{2(8)} \\ x_1=x_2=\frac{-16}{16}=-1 \end{gathered}[/tex]3) Since every real number is complex too as the Real set as a subset of the Complex Numbers set, hence, we can state that the root is also complex and it is -1
S={-1}
As the Discriminant is zero then, the parabola touches the x-axis on one single point x =-1.
