Respuesta :
Answer:
1.68x10^25 molecules of Cr2O3 are formed
Explanation:
1st) From the balanced reaction we know that 4 moles of Cr reacts with 3 moles of O2 to produce 2 moles of Cr2O3.
2nd) With the stoichiometry of the reaction, the given value of 1.34x10^3 grams of oxygen, the molar mass of oxygen (32g/mol) and the Avogadro's number (6.022*10^23 molecules/mol), we can calculate the number of molecules of Cr2O3:
[tex]1.34*10^3g\text{ O}_2*\frac{1\text{ mol O}_2}{32g\text{ O}_2}*\frac{2\text{ moles Cr}_2\text{O}_3}{3\text{ moles O}_2}*\frac{6.022\text{x10}^{23}\text{ molecules}}{1\text{ mol}}=1.68\text{x10}^{25}\text{ molecules}[/tex]So, 1.68x10^25 molecules of Cr2O3 are formed.
