We know that the components of any vector along the x and y axes are given by:
[tex]\begin{gathered} v_x=v\cos\theta \\ v_y=v\sin\theta \\ \text{ where:} \\ v\text{ is the magnitude of the vector.} \\ \theta\text{ is the angle from the }x\text{ axis to the vector. } \end{gathered}[/tex]
In this case we know the tha magnitude of the vector is 6.96 m/s; we also know that the angle from the x-axis to the vector is 51.5° (the sum of angles θ and the 26.5° angle); then we have:
[tex]\begin{gathered} v_x=6.96\cos51.5=4.33 \\ v_y=6.96\sin51.5=5.45 \end{gathered}[/tex]
Therefore, the components of the vector are:
[tex]\begin{gathered} v_x=4.33 \\ v_y=5.45 \end{gathered}[/tex]
