As given by the question
There are given that the function:
[tex]f(r)=\sqrt[]{r+2}-5[/tex]
Now,
(a):
To find the value of f(-2), put r = -2 into the given function:
Then,
[tex]\begin{gathered} f(r)=\sqrt[]{r+2}-5 \\ f(-2)=\sqrt[]{-2+2}-5 \\ f(-2)=\sqrt[]{0}-5 \\ f(-2)=-5 \end{gathered}[/tex]
Hence, the value of f(-2) is -5.
(b):
To find the value of f(98), put r = 98 into the given function:
Then,
[tex]\begin{gathered} f(r)=\sqrt[]{r+2}-5 \\ f(98)=\sqrt[]{98+2}-5 \\ f(98)=\sqrt[]{100}-5 \\ f(98)=10-5 \\ f(98)=5 \end{gathered}[/tex]
Hence, the value of the f(98) is 5.
Now,
(c):
To find the value of f(x-2), put r = x-2 into the given function:
So,
[tex]\begin{gathered} f(r)=\sqrt[]{r+2}-5 \\ f(x-2)=\sqrt[]{x-2+2}-5 \\ f(x-2)=\sqrt[]{x}-5 \end{gathered}[/tex]
Hence, the value of f(x-2) is shown below;
[tex]f(x-2)=\sqrt[]{x}-5[/tex]
