Consider a lightning bolt that carried a current of 13,000 A and transferred a total of 11 C of charge. How long did the lightning bolt last?

Answer:
8.5 x 10^(-4) s
Explanation:
The current I is equal to:
[tex]I=\frac{Q}{t}[/tex]Where Q is the charge and t is the time. Solving for t, we get:
[tex]t=\frac{Q}{I}[/tex]So, we need to replace Q = 11C and I = 13,000 A to get:
[tex]t=\frac{11C}{13,000A}=8.5\times10^{-4}s[/tex]Therefore, the lightning bolt lasts 8.5 x 10^(-4) seconds.