Explanation
Step1
let
[tex]\begin{gathered} \text{rate}=-50\frac{mt}{\text{sec}} \\ \text{rate}=\frac{dis\tan ce}{\text{time}} \end{gathered}[/tex][tex]\begin{gathered} y_1=initial\text{ position=0} \\ y_2=\text{ final positivion=-50} \\ \text{time}=\text{ 1 minute} \end{gathered}[/tex]Step 2
equation
[tex]\begin{gathered} time=\text{ }\frac{\text{distance}}{-50}\text{ Equation(1)} \\ \\ \text{replacing} \\ \text{time}=\frac{-450\text{ mt}}{-50\text{ }\frac{mt}{\min}} \\ \text{time}=9\text{ minutes} \end{gathered}[/tex]I hope this helps you
