The time taken by parcel to cover the vertical distance is,
[tex]t=\sqrt[]{\frac{2h}{g}}[/tex]Plug in the known values,
[tex]\begin{gathered} t=\sqrt[]{\frac{2(8000\text{ m)}}{9.8m/s^2}} \\ \approx40.4\text{ s} \end{gathered}[/tex]The horizontal distance covered by parcel is,
[tex]d=ut[/tex]Substitute known values,
[tex]\begin{gathered} d=(458\text{ m/s)(40.4 s)} \\ =18503.2\text{ m} \end{gathered}[/tex]Thus, the horizontal distance covered by parcel is 18503.2 m.
