the given problem can be exemplified in the following diagram:
The slope is defined as the tangent of the angle, therefore the slope is:
[tex]\begin{gathered} m=\tan 1.1 \\ m=1.96 \end{gathered}[/tex]
Therefore, the slope is 1.96.
When the rocket has travelled 66 yards, we have the following situation:
To determine the value of the height "y" we can use the function tangent since this function is defined as:
[tex]\tan x=\frac{opposite}{adjacent}[/tex]
Replacing the known values:
[tex]\tan 1.1=\frac{y}{66}[/tex]
Multiplying both sides by 66 we get:
[tex]66\tan 1.1=y[/tex]
Solving the operations:
[tex]129.7=y[/tex]
Therefore, the height is 129.7 yards.
When the rocket is at a height of 308 yards, we have the following situation:
we can use the tangent function. Replacing the known values we get:
[tex]\tan 1.1=\frac{308}{x}[/tex]
Multiplying both sides by "x":
[tex]x\tan 1.1=308[/tex]
Dividing both sides by tan 1.1:
[tex]x=\frac{308}{\tan 1.1}[/tex]
Solving we get:
[tex]x=156.8[/tex]
