If we had 8.02 x 10²⁴ atoms of neon, how many moles would this be?

Number of moles = 13.3 moles
The appropriate ratio will be 1/6.02*10²³
According to the Avogadro's constant;
[tex]\text{1mole}=6.02\times10^{23}atoms[/tex]Given the following parameters
Atoms of neon = 8.02 x 10²⁴ atoms
Find the moles of neon
[tex]\begin{gathered} moles\text{ of neon}=\frac{8.02\times10^{24}}{6.02\times10^{23}} \\ moles\text{ of neon=1.33}\times\frac{10^{24}}{10^{23}} \\ moles\text{ of neon}=1.33\times10^1 \\ moles\text{ of neon}=13.3moles \end{gathered}[/tex]Hence the number of moles this would be is approximately 13.3 moles
The appropriate ratio will be expressed as:
[tex]8.02\times10^{24}\times\frac{1}{6.02\times10^{23}}[/tex]