LyriaY495298 LyriaY495298
  • 25-10-2022
  • Mathematics
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Hi, can you help me answer this question please, thank you!

Hi can you help me answer this question please thank you class=

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ShreeJ681781 ShreeJ681781
  • 25-10-2022

[tex]x=\frac{130\cdot38}{100}=\frac{4940}{100}=49.4[/tex]

sample size=130

[tex]\text{proportion(p)=}\frac{49.4}{130}=0.38^{}[/tex]

q=1-p=1-0.38=0.62

z=1.96 from 95%

Therefore

[tex]ME=1.96\cdot\sqrt[]{\frac{0.38\cdot0.62}{130}}=0.083[/tex]

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