ANSWERS
• P(2) = 11
,
• P(-1) = 14
,
• P(0) = 7
EXPLANATION
Every time we have to evaluate a function, what we have to do is replace the variable with the value and solve the operations.
Let's solve P(2),
[tex]P(2)=3(2)^2-4(2)+7[/tex]
Solve the powers first,
[tex]P(2)=3\cdot4-4\cdot2+7[/tex]
Then the products,
[tex]P(2)=12-8+7[/tex]
And then the additions/subtractions,
[tex]P(2)=11[/tex]
The process is the same for the other two values,
[tex]P(-1)=3(-1)^2-4(-1)+7=3\cdot1-4(-1)+7=3+4+7=14[/tex]
And,
[tex]P(0)=3(0)^2-4(0)+7=3\cdot0-4\cdot0+7=0+0+7=7[/tex]
Hence, P(2) = 11, P(-1) = 14 and P(0) = 7.
