Find the equation of the line through the point (10,-6) that is perpendicular to the line with equation -11x-18y=-2070

SOLUTION:
Step 1:
In this question, we are given the following:
Find the equation of the line through the point (10,-6) that is perpendicular to the line with equation
-11x-18y=-2070
Step 2:
The details of the solution are as follows:
[tex]\begin{gathered} Given\text{ that:} \\ -11x\text{ - 18y = -2070} \\ We\text{ have that:} \\ -18y\text{ = 11x - 2070} \\ Divide\text{ both sides by -18, we have that:} \\ y\text{ = }\frac{11\text{ x}}{-18}\text{ }\frac{-2070}{-18} \\ Then,\text{ we have that:} \\ y\text{ = }\frac{-11\text{ x}}{18}\text{ + 115} \\ comparing\text{ this with:} \\ y\text{ = mx + c , then m = }\frac{-11}{18} \end{gathered}[/tex][tex]\begin{gathered} For\text{ perpendicular lines, we have that:} \\ m_1m_2=\text{ -1} \\ Then,\text{ we have that:} \\ m_2=\text{ -1 x }\frac{18}{-11}=\text{ }\frac{18}{11} \\ Hence,\text{ m}_2=\frac{18}{11} \end{gathered}[/tex][tex]\begin{gathered} We\text{ have the point:} \\ (\text{ 10 , - 6 \rparen} \\ Using\text{ the formulae:} \\ y\text{ - y}_1=\text{ m}_2\text{ \lparen x - x}_1) \end{gathered}[/tex][tex]\begin{gathered} We\text{ have that:} \\ y\text{ - \lparen-6\rparen =}\frac{18}{11}\text{ \lparen x - 10 \rparen} \\ Multiply\text{ through by 11, we have that:} \\ 11y\text{ + 66 = 18x - 180} \\ Rearranging,\text{ we have that:} \\ 11y\text{ = 18x -180 - 66} \\ 11y\text{ = 18 x -246} \end{gathered}[/tex]CONCLUSION:
The final answer is:
[tex]11\text{ y = 18 x - 246}[/tex]