A man pushes a 35.2-kilogram box across a frictionless floor with a force of 128 Newtons. What is the acceleration of the box?

Respuesta :

ANSWER:

3.636 m/s^2

STEP-BY-STEP EXPLANATION:

We have the following formula, which is the force formula:

[tex]\begin{gathered} F=m\cdot a \\ m=\text{ mass = 35.2 kg} \\ F=\text{ force = 128 N} \\ a=\text{ acceleration} \end{gathered}[/tex]

Replacing and solving for a (acceleration):

[tex]\begin{gathered} 128=35.2\cdot a \\ a=\frac{128}{35.2} \\ a=3.636m/s^2 \end{gathered}[/tex]

Therefore, the acceleration is equal to 3.636 m/s^2