14 cans of soup
1) Gathering the data
Price of sale: $ 2.25
Coupon: $3
No more than $30 (≤30)
2) We can write out the following inequality, considering all that data:
[tex]2.25x-3\leq30[/tex]Note that the coupon offers her a discount of $3. So now, we can solve that:
[tex]\begin{gathered} 2.25x-3\leq30 \\ 2.25x-3+3\leq30+3 \\ 2.25x\leq33 \\ \frac{2.25x}{2.25}\leq\frac{33}{2.25} \\ x\leq14.67 \end{gathered}[/tex]Note that, there is not a 14.6 can so let's round it off to the nearest lower whole number and check it:
[tex]\begin{gathered} 2.25(14)-3\leq30 \\ 31.5-3\leq30 \\ 28.5\leq30True \end{gathered}[/tex]3) Hence, the answer is 14 cans of soup
