Given:
There are given the points:
[tex](2,3),and,(6,11)[/tex]Explanation:
According to the question:
We need to find the equation:
So,
To find the equation, first, we need to find the slope of the line:
So,
From the formula of slope:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Then,
[tex]\begin{gathered} m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ m=\frac{11-3}{6-2} \\ m=\frac{8}{4} \\ m=2 \end{gathered}[/tex]Now,
From the formula to find the equation of line:
[tex]y-y_1=m(x-x_1)[/tex]Then,
[tex]\begin{gathered} y-y_{1}=m(x-x_{1}) \\ y-3=2(x-2) \\ y-3=2x-4 \\ y=2x-4+3 \\ y=2x-1 \end{gathered}[/tex]Final answer:;
Hence, the equation of the line is shown below:
[tex]y=2x-1[/tex]