Given the equation of the line in point-slope form:
[tex]y-3=\frac{9}{5}(x+1)[/tex]Based on this, one point of the line is (-1, 3). Now, the slope-intercept form of the equation is:
[tex]\begin{gathered} y-3=\frac{9x}{5}+\frac{9}{5} \\ y=\frac{9}{5}x+\frac{9}{5}+3 \\ \Rightarrow y=\frac{9}{5}x+\frac{24}{5} \end{gathered}[/tex]Then, another point of the line is (0, 24/5) = (0, 4.8). Finally, the graph of the equation is:
