Respuesta :
Answer
41.2 L
Explanation
Given that:
The mass of oxygen gas (O₂) = 58.9 grams
What to find:
The volume of 58.9 grams of oxygen gas (O₂) at STP.
Step-by-step solution:
The first step is to convert 58.9 grams of oxygen gas (O₂) given to moles using the mole formula:
[tex]Moles=\frac{Mass}{Molar\text{ }mass}[/tex]The molar mass of oxygen gas (O₂) is 31.998 g/mol.
[tex]Moles\text{ }of\text{ }O_2=\frac{58.9g}{31.998g\text{/}mol}=1.8407\text{ }mol[/tex]The final step is to convert the 1.8407 moles of oxygen gas (O₂) to volume using the conversion factor below.
Conversion factor: The molar volume of any gas at STP is 22.4 L. That is, one mole of any gas has a volume of 22.4 L or 22,400 mL.
So,
[tex]\begin{gathered} 1\text{ }mol\text{ }O_2=22.4\text{ }L \\ \\ 1.8407\text{ }mol\text{ }O_2=x \\ \\ x=\frac{1.8407\text{ }mol}{1\text{ }mol}\times22.4\text{ }L \\ \\ x=41.2\text{ }L \end{gathered}[/tex]