Given that on trial mix, Juan's mother uses 5/6 cup almonds. 2/3 cup peanuts, 1/4 cup cereal and 1/2 cup raisins.
Make the denominator of all equal to lcm(6,3,4,2) = 12.
Theb:
[tex]\begin{gathered} \frac{5}{6}=\frac{10}{12} \\ \frac{2}{3}=\frac{8}{12} \\ \frac{1}{4}=\frac{3}{12} \\ \frac{1}{2}=\frac{6}{12} \end{gathered}[/tex]
Now, just check the value in the numerator.
[tex]\begin{gathered} 3<6<8<10 \\ \frac{3}{12}<\frac{6}{12}<\frac{8}{12}<\frac{10}{12} \\ \text{Cereal < Raisins }<\text{Peanuts}<\text{Almonds} \end{gathered}[/tex]
