The equation of line with the slope m in the slope intercept form is :
y = mx + b
Slope can express as :
[tex]\text{ Slope=}\frac{y_2-y_1}{x_2-x_1}[/tex]Substitute the value :
[tex](x_1,y_1)=(0,3),(x_2,y_2)=(-8,15)[/tex][tex]\begin{gathered} \text{ Slope=}\frac{y_2-y_1}{x_2-x_1} \\ Sl\text{ope=}\frac{15-3}{-8-0} \\ \text{ slope=}\frac{12}{-8} \\ \text{slope}=\frac{3}{-2} \end{gathered}[/tex]Substitute the value of slope in the equation of line:
[tex]\begin{gathered} y-3=\frac{3}{-2}(x-0) \\ y-3\text{ =-}\frac{3}{2}x \\ y=-\frac{3}{2}x+3 \end{gathered}[/tex]Equation of line in slope intercept form is :
y = -3/2x + 3
Slope = -3/2
Answer : y = -3/2x + 3
Slope = -3/2
