Given that
y = 1/4x + 4
x + y = -1
For the first equation,
Let us find the x intercept by making x equals to 0
[tex]\begin{gathered} y\text{ = }\frac{1}{4}x\text{ + 4} \\ \text{let x = 0} \\ y\text{ = }\frac{1}{4}(0)\text{ + 4} \\ \text{y = 0 + 4} \\ \text{y = 4} \end{gathered}[/tex]To find x, let y = 0
[tex]\begin{gathered} y\text{ = }\frac{1}{`4}x\text{ + 4} \\ \text{y = }\frac{x}{4}\text{ + 4} \\ \text{Common denominator = 4} \\ y\text{ = }\frac{x\text{ + 16}}{4} \\ \text{Cross multiply} \\ 4y\text{ = x + 16} \\ \text{make y = 0} \\ 4(0)\text{ = x + 16} \\ \text{0 = x + 16} \\ x\text{ =-16} \end{gathered}[/tex]Therefore, we have (0, 4) and (-16, 0)
For the second equation
x + y = -1
To find the x - intercept, make x = 0
0 + y = -1
y = -1
(0, -1)
To find x, let y = 0
x + y = -1
x + 0 = -1
x = -1
(-1, 0)
Therefore, the two points are (-1, 0) and (0, -1)
The above points can now be graph
The diagram above is just an illustration on how to graph the given points
From the numbered graph, their point of intersection is (-4, 3)
x = -4 and y = 3
