To find the angle we have the formula
and we have that
[tex]\begin{gathered} \lvert{a}\rvert=\sqrt{4+25}=\sqrt{29} \\ \lvert b\rvert=\sqrt{16+441}=\sqrt{457} \end{gathered}[/tex]so we get that
[tex]\cos\alpha\approx-0.8425867691776014[/tex]Then
[tex]\alpha=147.41429264608558°[/tex]The answer is 147.41429264608558