Given that events A and B are independent with P(A)=0.85 and P(B) = 0.3,determine the value of P(A|B), rounding to the nearest thousandth, if necessary.

Respuesta :

The Solution.

Given that

[tex]\begin{gathered} P(A)=0.85 \\ P(B)=0.3 \end{gathered}[/tex]

The conditional probability P(A/B) is given as

[tex]P(A|B)=\frac{P(A\cap B)}{P(B)}[/tex]

But for independent events, we have that

[tex]P(A\cap B)=P(A)\times P(B)[/tex]

Hence, it follows that

[tex]\begin{gathered} P(A|B)=\frac{P(A)\times P(B)}{P(B)}=P(A)=0.85\approx0.850 \\ \text{though the nearest thousandth is not necessary.} \end{gathered}[/tex]

Therefore, the correct answer is 0.85 ( 0.850 if you consider it necessary)