Respuesta :
Given:
Here two cylindrical containers are given with named A and B and the measures are 1.2 m height 4.6 m diameter and 12 meter height and 8 m in diameter respectively.
Required:
We need to find that what is the difference in the amount of water cylindrical A and cylindrical B will contain to the nearest hundredth.
Explanation:
Lets consider measures A as 1 and measures B as 2 means
measures of cylinder A is
[tex]\begin{gathered} r_1=\frac{4.6}{2}=2.3\text{ m} \\ h_1=1.2\text{ m} \\ \end{gathered}[/tex]measure of cylinder A is
[tex]\begin{gathered} r_2=\frac{8}{2}=4\text{ m} \\ h_2=12\text{ m} \end{gathered}[/tex]now find the volume of named A contained
[tex]V_A=\pi r_1^2h_1=3.14*2.3*2.3*1.2=19.94\text{ m}^3[/tex]now for B
[tex]V_B=\pi r_2^2h_2=3.14*4*4*12=603.19\text{ m}^3[/tex]now to find the difference
[tex]V_B-V_A=603.19-19.94=583.25\text{ m}^3[/tex]Final answer:
Difference of both container is 583.25 cubic meter
