We have to find the list price P.
We know that the net cost was C = $4312.40 and the series discount was 5/10/15 (d1 = 0.05, d2 = 0.10 and d3 = 0.15).
We can write the relation between this values as:
[tex]C=P(1-d_1)(1-d_2)(1-d_3)[/tex]We can replace and solve as:
[tex]\begin{gathered} C=P(1-d_1)(1-d_2)(1-d_3) \\ 4312.40=P(1-0.05)(1-0.10)(1-0.15) \\ 4312.40=P\cdot0.95\cdot0.90\cdot0.85 \\ 4312.40=P\cdot0.72675 \\ P=\frac{4312.40}{0.72675} \\ P=5933.81 \end{gathered}[/tex]Answer: the list price was $5933.81.
