Find the surface area of the "unrolled" cylinder where a = 4 cm and b = 8 cm.Leave your answer in terms of t.

The surface area of the cylinder is:
[tex]96\pi[/tex]Explanation:The surface area of the cylinder is:
[tex]\begin{gathered} 2\pi r^2+2\pi rh \\ =2\pi(4^2)+2\pi(4)(8) \\ =32\pi+64\pi \\ =96\pi \end{gathered}[/tex]Where r is the radius and h is the height