Respuesta :

Quadratic Function

The general form of a quadratic equation is:

[tex]y=ax^2+bx+c[/tex]

Comparing this equation with the given function:

[tex]y=1x^2+bx+c[/tex]

It's clear that

a=1

We don't know the values of b and c.

To find them, we use the vertex form of the quadratic equation:

[tex]y=a\mleft(x-h\mright)^2+k[/tex]

Where the point (h,k) are the coordinates of the vertex.

Substituting the coordinates of the vertex (3,8):

[tex]y=a(x-3)^2+8[/tex]

Expanding the square and substituting a=1:

[tex]y=x^2-6x+9+8=x^2-6x+17[/tex]

The equation is now in standard form, and we can easily identify the values of b and c:

b = -6

c = 17