Given,
The equation of the function is,
[tex]y=5+8sin(5\theta+\frac{3\pi}{4})[/tex]
Required
The vertical shhift of the function.
The standard form of the function is,
[tex]\begin{gathered} y=Asin(Bx+C)+D \\ Here\text{ A = amplitude} \\ B=period \\ C\text{ = phase shift} \\ D=vertical\text{ shift} \end{gathered}[/tex]
Comapring the given function with standard form then it obtain that the vertical shift is of 5 units.
Hence, the vertical shift of the curve is 5 units.
