[tex]\begin{gathered} a_n=1+(n-1)\cdot2 \\ a_{24}=47 \end{gathered}[/tex]
11) Let's firstly examine the sequence:
[tex]\begin{gathered} 1,3,5,7 \\ a_1=1 \\ d=2 \end{gathered}[/tex]
Note that the first term is 1, and this sequence goes increasing by 2 units so the common difference is d=2
2) So we can write an Explicit formula for that Arithmetic Sequence, and then find the 24th term:
[tex]\begin{gathered} a_n=a_1+(n-1)d \\ a_{24}=1+(24-1)2 \\ a_{24}=1+23\cdot2 \\ a_{24}=1+46 \\ a_{24}=47 \end{gathered}[/tex]
Note that we multiplied the difference by (n-1), in this case, n=24
3) Hence, the 24th term is 47 and the equation is an=1+(n-1)2
