Given:
[tex]T_c=(T_f-32)\frac{5}{9}[/tex]
Evaluate for T_f
[tex]\begin{gathered} 9\times T_c=(T_f-32)5 \\ \frac{\begin{equation*}9\times T_c\end{equation*}}{5}=\frac{(T_f-32)5}{5} \\ \frac{9\times T_c}{5}=T_f-32 \\ \frac{9}{5}T_c+32=T_f \\ \therefore T_f=\frac{9}{5}T_c+32 \end{gathered}[/tex]
Hence,
[tex]\begin{gathered} \begin{equation*} T_f=\frac{9}{5}T_c+32 \end{equation*} \\ \\ This\text{ means the product of }\frac{9}{5}\text{ and }T_c\text{ plus 32.} \end{gathered}[/tex]
