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25-10-2022
Mathematics

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We an equivalent agression for 40+8(n-3)

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KemberA421460 KemberA421460

25-10-2022

Answer:

8n+16

Explanation:

Given the expressions:

[tex]40+8\left(n-3\right)[/tex]

First, distribute 8 over the terms in the bracket:

[tex]\begin{gathered} =40+8(n)+8(-3) \\ =40+8n-24 \end{gathered}[/tex]

Finally, collect like terms and simplify:

[tex]\begin{gathered} =40-24+8n \\ =16+8n \end{gathered}[/tex]

An equivalent expression is 8n+16.

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