Given a table represents a relation between x and y
As shown, the change of (x) and (y) vary with a constant rate
So, the table represents a linear function
The general equation will be: y = m * x + b
where (m) is the slope, (b) is the value of y when (x=0)
So, from the table, when x = 0 , y = 25
The slope will be as follows:
[tex]m=\frac{30-25}{1-0}=\frac{5}{1}=5[/tex]So, the equation will be:
[tex]y=5x+25[/tex]When the input = 200, x = 200
So, substitute with (x) to find the output (y)
[tex]y=5\cdot200+25=1000+25=1025[/tex]So, the answer will be:
For an input 200, the output is 1025
===================================================
Another method to solve using the arithmetic sequence.
As shown in the table consider (x) represents the number of terms
So, (y) will be an arithmetic sequence
The first term = a = 30
The common difference = d = 35 - 30 = 5
the general rule of the arithmetic sequence is:
[tex]y_{}=a+d(x-1)[/tex]substitute with (a) and (d)
[tex]y=30+5(x-1)[/tex]When x = 200
[tex]y=30+5(200-1)=30+5\cdot199=1025[/tex]So, for an input 200, the output = 1025
