Consider the given linear equation,
[tex]12x-4y=48[/tex]PART A
Substitute y=0 to obtain the x-intercept,
[tex]\begin{gathered} 12x-4(0)=48 \\ 12x=48 \\ x=4 \end{gathered}[/tex]Thus, the x-intercept is 4 .
Substitute x=0 to obtain the y-intercept,
[tex]\begin{gathered} 12\mleft(0\mright)-4y=48 \\ -4y=48 \\ y=-12 \end{gathered}[/tex]Thus, the y-intercept is -12 .
Therefore, option C is the correct choice
PART B
The linear equation can also be written as,
[tex]\begin{gathered} 4y=12x-48 \\ y=\frac{12}{4}x-\frac{48}{4} \\ y=3x-12 \end{gathered}[/tex]The minimum limit to make a profit can be calculated as,
[tex]\begin{gathered} y>0 \\ 3x-12>0 \\ 3x>12 \\ x>\frac{12}{3} \\ x>4 \end{gathered}[/tex]Note that the order of photograph must be an integer. The next integer after 4 is 5.
So the minimum order size to make a profit should be 5.
