To compare we have to rearrange the function.
First, we define f(x) as the square root function:
[tex]f(x)=\sqrt[]{x}[/tex]Then, we rearrange g(x):
[tex]g(x)=\sqrt[]{\frac{16x}{36}=\frac{\sqrt[]{16}\cdot\sqrt[]{x}}{\sqrt[]{36}}=\frac{4\cdot\sqrt[]{x}}{6}=\frac{2}{3}\cdot f(x)}[/tex]Then, we see that g(x) is 2/3 times the square root function.
The answer is "B. The graph is shrunk by a factor of 2/3".
