So,
We're going to solve the following equation:
[tex]\frac{7}{2}p-\frac{11}{12}=\frac{5}{9}[/tex]The first thing we need to do, is to pass all the numbers (independent terms) to the other side of the equation, and let the variable p in the other side.
Notice that if we pass the numbers to the other side, they will pass with the opposite sign. Like this:
[tex]\frac{7}{2}p=\frac{11}{12}+\frac{5}{9}[/tex]Now we're going to sum the fractions:
[tex]\begin{gathered} \frac{7}{2}p=\frac{99+60}{108} \\ \\ \frac{7}{2}p=\frac{159}{108} \end{gathered}[/tex]Now, we just multiply the denominator to the other side, and divide by the numerator:
[tex]p=\frac{159\cdot2}{108\cdot7}=\frac{318}{756}[/tex]Simplifying, we got that:
[tex]p=\frac{53}{126}[/tex]Example:
Suppose you have the equation:
[tex]x-1=2[/tex]We are looking for let the variable "x" alone in a side of the equation, so, to do this we could sum "1" to both sides:
[tex]\begin{gathered} x-1+1=2+1 \\ x=3 \end{gathered}[/tex]The same thing happens in this problem.
