Given:
Equation of a circle
[tex](x+4)^2+y^2=7[/tex]
Required:
Find the center and radius of the circle. Then graph of circle.
Explanation:
We have a standard equation of circle
[tex](x-h)^2+(y-k)^2=r^2[/tex]
Whose radius is (h, k) and radius r.
We have equation of a circle
[tex](x+4)^2+y^2=7[/tex]
Now, we will compare with standard equation of a circle
[tex]We\text{ will get center\lparen-4, 0\rparen and radius }\sqrt{7}.[/tex]
Graph of circle is
Answer:
Hence, this is the answer.
