6)
the equation is:
[tex]3x-2y=-4[/tex]
So we need two poinds to graph the line so I can replace X=0 so:
[tex]\begin{gathered} -2y=-4 \\ y=\frac{4}{2} \\ y=2 \end{gathered}[/tex]
So the first coordinate is (0,2) and now we replace y=0 so:
[tex]\begin{gathered} 3x=-4 \\ x=-\frac{4}{3} \\ x=1.33 \end{gathered}[/tex]
So the secon coordinate is (1.33,0), So now we can graph it:
7)
The equation is:
[tex]y=\lvert x-5\rvert-3[/tex]
This is an absolut value that is translate 5 units to the right and 3 units down, what menas the vertex is in the coordinate (5,-3), now we evaluate one point at the right and one at the left of the vertex so we evaluate it in x=0 and x=6
for x=0 will be:
[tex]\begin{gathered} \lvert-5\rvert-3=y \\ 5-3=y \\ 2=y \end{gathered}[/tex]
Now for x=6
[tex]\begin{gathered} \lvert6-5\rvert-3=y \\ 1-3=y \\ -2=y \end{gathered}[/tex]
So the graph will be:
