A baseball pitcher won 85 % of the games he pitched. If he pitched 40 ballgames , how many games did he win ?

SOLUTION
The total games pitched is 40
Let number of games he win be y.
Then the ratio of the game win to the total game is
[tex]\frac{y}{40}[/tex]The percentage of game won by the pitcher is
[tex]85\text{ \%}[/tex]Then, the ratio of this percentage will be
[tex]\frac{85}{100}[/tex]Equate both ratio we have
[tex]\frac{y}{40}=\frac{85}{100}[/tex]Take cross product of the equation above
[tex]\begin{gathered} 100y=85\times40 \\ 100y=3400 \end{gathered}[/tex]Divide both sides of the equation by 100.
[tex]\begin{gathered} \frac{100y}{100}=\frac{3400}{100} \\ \text{Then} \\ y=34 \end{gathered}[/tex]Therefore, the Baseball picher won 34 of the games he pitched.
Answer is 34