SOLUTION AND EXPLANATION
The distance between two-point A and B is given as
[tex]|AB|=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]
From the diagram in the question the two-point given are
[tex]\begin{gathered} A(1,3)\text{ } \\ B(6,6)^{} \end{gathered}[/tex]
Where
[tex]x_1=1,x_2=6,y_1=3,y_2=6[/tex]
Substitute the parameters into the formula above
[tex]\begin{gathered} |AB|=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2} \\ |AB|=\sqrt[]{(6-3)^2+(6-1)^2} \\ |AB|=\sqrt[]{3^2+5^2} \\ |AB|=\sqrt[]{9+25} \\ |AB|=\sqrt[]{34} \end{gathered}[/tex]
Hence, the distance between the two points is
[tex]|AB|=5.8\text{units}[/tex]
Therefore the distance between the two-point is 5.8unit to the nearest tenth
The Third option is correct
