Let's draw a diagram of the problem:
Where:
a, b, and c, are distances.
We can find a and b as follows:
[tex]\begin{gathered} b=1.75h\cdot195\frac{mi}{h}=341.25mi \\ a=2.75h\cdot195\frac{mi}{h}=536.25mi \end{gathered}[/tex]
Now, we can use the law of cosines in order to find c:
[tex]\begin{gathered} c=\sqrt[]{a^2+b^2-2ab\cos (B)} \\ c=\sqrt[]{(536.25)^2+(341.25)^2-2(536.25)(341.25)\cos (125)} \\ c\approx784mi \end{gathered}[/tex]
Answer:
She is 784mi from ther starting position
