Given:
The initial velocity of the pumpkin is
[tex]v_o=960\text{ ft/s}[/tex]To find the maximum height of the pumpkin
and the time for which pumpkin will be air.
Explanation:
When the pumpkin reaches maximum height its final velocity will be
[tex]v_f=\text{ 0 ft/s}[/tex]The equation used to calculate the maximum height will be
[tex]v_f^2=v_o^2-2gh[/tex]Here, the value of g is the acceleration due to gravity whose value is 32.18 ft/s^2.
On substituting the values, the maximum height will be
[tex]\begin{gathered} 0=(960)^2-2\times32.18\times h \\ h=\frac{(960)^2}{2\times32.18} \\ =14319.45\text{ ft} \end{gathered}[/tex]