Given a solenoid with 8 turns. A magnet is dropped through the middle of the solenoid, and this induces an average voltage of 4.00 volts in the solenoid over a time of 6.00 s. What was the average change in magnetic flux through one turn in the solenoid in SI units? a)1.50B)3.00c)0.750

Respuesta :

Given:

The number of turns in the solenoid, N=8

The induced voltage, V=4.00 V

The time interval, Δt=6.00 s

To find:

The average change in the magnetic flux.

Explanation:

The emf induced due to the changing magnetic flux is given by the equation,

[tex]V=N\frac{\Delta\phi}{\Delta t}[/tex]

Where Δφ is the change in the magnetic flux.

On rearranging the above equation,

[tex]\Delta\phi=\frac{V\times\Delta t}{N}[/tex]

On substituting the known values in the above equation,

[tex]\begin{gathered} \Delta\phi=\frac{4.00\times6.00}{8} \\ =3.00\text{ Wb} \end{gathered}[/tex]

Final answer:

Thus the average change in the magnetic flux through one turn in the solenoid is 3.00 Wb. Thus the correct answer is option B.