You know that the Function A is:
[tex]y=\frac{2}{3}x+6[/tex]
Substitute the given value of "x" into the Function A:
[tex]\begin{gathered} y=\frac{2}{3}x+6 \\ \\ y=\frac{2}{3}(9)+6 \end{gathered}[/tex]
Evaluating, you get:
[tex]\begin{gathered} y=\frac{18}{3}+6 \\ \\ y=6+6 \\ \\ y=12 \end{gathered}[/tex]
Given the Function B shown in the table, you need to identify the Input value 9 (or the x-value) and its corresponding Output value (or y-value).
In this case, when the value of "x" is:
[tex]x=9[/tex]
The value of of "y" is:
[tex]y=7[/tex]
Since the Output value in Function B is less than the the Output value in Function A when the value of "x" is 9, you can determine that the the answer is:
