The area of the museum is given by:
[tex]\begin{gathered} A=\pi r^2 \\ \text{Where:} \\ r=30m \\ A=\pi(30^2)=900\pi\approx2827m^2 \end{gathered}[/tex]
The area of the school is:
[tex]\begin{gathered} A=w\cdot l \\ \text{where:} \\ w=\text{width} \\ l=\text{length} \\ w=\sqrt[]{30^2+10^2}=10\sqrt[]{10} \\ l=\sqrt[]{60^2+20^2}=20\sqrt[]{10} \\ A=(10\sqrt[]{10})(20\sqrt[]{10})=2000m^2 \end{gathered}[/tex][tex]2827m^2-2000m^2=827m^2[/tex]
The area of the school is about 827m² less than the area of the museum
