Use the discriminant to find the nature of the solutions to the following quadratic equation
3x^2 +x-3=0
Two imaginary number solutions
one repeated rational solution
one repeated irrational number solution
Two different irrational number solutions
Two different rational number solutions.
we know that
the discriminant of a quadratic equation is
[tex]D=b^2-4ac[/tex]we have
[tex]3x^2+x-3=0[/tex]so
a=3
b=1
c=-3
substitute in the equation Of discriminant
[tex]\begin{gathered} D=(1^2)-4\cdot(3)\cdot(-3) \\ D=1+36 \\ D=37 \end{gathered}[/tex]we have that
D >0
that means
