The radical given is,
[tex]\sqrt[]{34}[/tex]
To resolve this, we will look for a perfect square will is smaller to the square root of 34 and a perfect which is larger than 34.
Therefore, the two squares are 25 and 36.
Hence,
[tex]\sqrt[]{34}\text{ lies between }\sqrt[]{25}\text{ and }\sqrt[]{36}[/tex]
Then,
[tex]\begin{gathered} \sqrt[]{25}=5 \\ \sqrt[]{36}=6 \end{gathered}[/tex]
Hence,
[tex]\sqrt[]{34}\text{ falls between 5 and 6}[/tex]
which is,
[tex]5<\sqrt[]{34}<6[/tex]
Final answer
[tex]5<\sqrt[]{34}<6[/tex]
