Respuesta :
check the picture below
recall your SOH CAH TOA
[tex]\bf in(\theta)=\cfrac{opposite}{hypotenuse} \qquad \qquad % cosine cos(\theta)=\cfrac{adjacent}{hypotenuse} \\ \quad \\ % tangent tan(\theta)=\cfrac{opposite}{adjacent}[/tex]
we have,
the angle,
the hypotenuse,
we want the opposite side
which of those fellows have only that? ahhhh it has to be Ms Sine,
so let's ask her
[tex]\bf sin(\theta)=\cfrac{opposite}{hypotenuse}\implies sin(75^o)=\cfrac{x}{100}\implies 100\cdot sin(75^o)=x[/tex]
the opposite side "x", is how tall the tree is
when taking the sine function, make sure your calculator is in Degree mode, since the angle is in degrees
recall your SOH CAH TOA
[tex]\bf in(\theta)=\cfrac{opposite}{hypotenuse} \qquad \qquad % cosine cos(\theta)=\cfrac{adjacent}{hypotenuse} \\ \quad \\ % tangent tan(\theta)=\cfrac{opposite}{adjacent}[/tex]
we have,
the angle,
the hypotenuse,
we want the opposite side
which of those fellows have only that? ahhhh it has to be Ms Sine,
so let's ask her
[tex]\bf sin(\theta)=\cfrac{opposite}{hypotenuse}\implies sin(75^o)=\cfrac{x}{100}\implies 100\cdot sin(75^o)=x[/tex]
the opposite side "x", is how tall the tree is
when taking the sine function, make sure your calculator is in Degree mode, since the angle is in degrees
